3x^2-10=118

Solution for 3x^2-10=118 equation:

3x^2-10=118

We move all terms to the left:

3x^2-10-(118)=0

We add all the numbers together, and all the variables

3x^2-128=0

a = 3; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·3·(-128)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{6}}{2*3}=\frac{0-16\sqrt{6}}{6}
=-\frac{16\sqrt{6}}{6}
=-\frac{8\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{6}}{2*3}=\frac{0+16\sqrt{6}}{6}
=\frac{16\sqrt{6}}{6}
=\frac{8\sqrt{6}}{3}
$